|
The combustion of
propane is exothermic so the temperature will increase. The reaction results
in an increase in the number of moles as 1 molecule of propane combines with 5 molecules of oxygen to produce 3 molecules of CO2 and 4 molecules of
water. As a result of the increase in T and the number of molecules in the system, the pressure will
increase. So, the process is neither isothermal nor isobaric. The volume of the rigid bomb calorimeter remains constant
throughout this process. Therefore, this process is an isochoric process. |